• electric-car energy model

    From Jonathan Thornburg [remove -color to reply]@dr.j.thornburg@gmail-pink.com to sci.physics.research on Sun Dec 22 08:57:10 2024
    From Newsgroup: sci.physics.research

    What determines the energy consumption and driving range of a modern
    electric car? Applying some elementary physics, it's quite easy to
    construct an energy model and make rough estimates for the various
    parameters.

    Let's start with the usable battery capacity (available energy) E_total.
    This is usually quoted in kilowatt-hours (kWh) (= 3.6e6 Joules). Let's consider a 100%-down-to-0% full discharge of the battery, even though
    practical usage normally only uses a fraction of the battery capacity.
    And let's assume driving at a steady speed on paved, level roads, with
    no headwinds/tailwinds.

    When driving at any but the slowest of speeds, most of the energy goes
    into turning the car's wheels, doing work against aerodynamic drag and
    tire friction. This process involves battery power (typically starting
    out as high-voltage DC from many battery cells in series) being converted
    into whatever voltage and current the drive motor(s) use (modulated by
    the accelerator-pedal position), the driving electric motor(s) converting
    this to mechanical rotation, and the drivetrain converting this rotation
    into mechanical rotation of the driving wheels (loosing some energy to
    bearing friction and other mechanical losses). None of these processes
    are 100% efficient; let's call the net efficiency from battery energy to rotation of the driving wheels eta_drivetrain.

    If the car is 2-wheel-drive there's also some energy lost in wheel-bearing friction in the non-driving wheels; for simplicity we'll ignore this, or equivalently lump it into eta_drivetrain.

    This web page
    https://www.reddit.com/r/teslamotors/comments/ja89w1/tesla_model_3_lr_performance_consumption/
    suggests that for one popular model of electric car, eta_drivetrain is
    on the order of 0.8, so we'll use that as our estimate.

    How much power P_at_wheels is needed at the wheels to move the car?
    If the car is moving at a (constant) speed v, the work-energy theorem
    gives
    P_at_wheels = F_drag v
    where F_drag is the overall drag force.

    There are two main energy-dissipation mechanisms: air resistance and dissipation in flexing the tires,
    so we take
    F_drag = F_drag,air + F_drag,tires.

    For the high--Reynolds-number regime appropriate to cars, the air
    resistance drag is well-approximated by
    F_drag,air = 1/2 C_d rho A v^2
    where rho is the density of air (1.2 kg/m^3 at sea level & standard temperature, falling in well-known ways with increasing altitude and/or temperature), C_d is a dimensionless drag coefficient depending on the
    car's shape (C_d is typically around 0.25 to 0.4 for modern cars), A
    is the car's frontal area (on the order of a few m^2), and v is again
    the driving speed.

    According to the web page
    https://www.engineeringtoolbox.com/rolling-friction-resistance-d_1303.html tire drag (on a smooth paved road) can be approximated by
    F_drag,tires = C_rolling mg
    where mg is the car's weight (empty weight + people + any cargo) and
    C_rolling is a dimensionless drag coefficient given approximately by
    C_rolling = 0.005 + (0.01 + 0.0095 v_100^2)/p_bar
    where p_bar is the tire pressure (I presume above atmospheric pressure)
    in units of bars (1 bar = 1e5 Pascal = about 15 lb/inch^2) and v_100
    is the car's speed in units of 100 km/hr.

    (Because F_drag,tires is (in this approximation) linear in mg, we don't
    need to worry about the car's weight distribution.)

    There is also some energy used for non-propulsion purposes. This
    may include cabin heating and windshield defrosters, air conditioning,
    battery heating or cooling, windshield wipers, headlights, power steering/brakes, power windows, collision-avoidance radar, and dashboard
    and other miscellaneous onboard electrical/electronic equipment. This "overhead" varies widely depending on ambient conditions; notably, cabin
    and battery heating/cooling may vary from zero to many kilowatts.

    As a (very) crude approximation let's model this as a constant power
    draw from the battery, converted to whatever voltage/current the various equipment uses at an average efficiency of eta_overhead to provide a
    (constant) usable power of P_overhead all the time the car is turned
    on. For moderate temperatures where none of cabin/battery heating,
    windshield defrosters, or air conditioning are operating, let's estimate P_overhead = 200 Watts and eta_overhead = 0.7. (This is < eta_drivetrain because I suspect the main drivetrain is heavily optimized for maximum efficiency, whereas the smaller motors and power supplies are probably optimized more for minimum cost.)

    Putting all the pieces together, the drivetrain power drawn from the
    battery is
    F_drag v/eta_drivetrain
    while the overhead power drawn from the battery is
    P_overhead/eta_overhead
    so that the total power drawn from the battery is the sum of these,
    F_drag v/eta_drivetrain + P_overhead/eta_overhead

    Thus the time to completely deplete an initially-fully-charged battery
    is
    E_total / (F_drag v/eta_drivetrain + P_overhead/eta_overhead)
    and the distance driven (i.e., car's range) d is
    d = v E_total / (F_drag v/eta_drivetrain + P_overhead/eta_overhead)
    = E_total / (F_drag/eta_drivetrain + P_overhead/(v eta_overhead))

    Inserting some numbers for my car,
    E_total = 64 kWh = 230e6 Joules
    p_bar = 2.25
    A = 2.5 m^2
    C_d = 0.35
    m = 2000 kg
    and driving speeds of
    v_100 = 0.5 (for driving at 50 km/h), 0.8 (80 km/hr), or 1.2 (120 km/h)
    (i.e., v = 13.9, 22.2, or 33.3 m/s respectively)
    I get
    C_rolling = 0.0105, 0.0121, and 0.0155 respectively
    C_drag = 0.35
    F_drag,tires = 206, 238, and 304 Newtons respectively
    F_drag,air = 101, 259, and 582 Newtons respectively
    with the final result
    d = 569, 363, and 206 km respectively

    These numbers are within 20% or so of reality (that's closer than I was expecting before doing the calculation!), suggesting that at least the
    major components of our model (drivetrain efficiency, tire drag at low
    speeds, and air resistance at high speeds) are roughly correct.

    The sharp drop-off in range with increasing speed is particularly notable
    (and quite realistic).
    --
    -- "Jonathan Thornburg [remove -color to reply]" <dr.j.thornburg@gmail-pink.com>
    currently on the west coast of Canada
    "The programmers outside looked from Web 2.0 firm to AI company, and from
    AI company to Web 2.0 firm, and from Web 2.0 firm to AI company again;
    but already it was impossible to say which was which."
    -- /Ars Technica/ comment by /ubercurmudgeon/, 2024-05-09 --- Synchronet 3.21b-Linux NewsLink 1.2