In the animation https://www.geogebra.org/classic/sr8fxezb there is the
force F of the hand that pushes the point A of the car.
=20
The force F that pushes the car is certainly a "net" force because
there is no one to push the car from the other side.
=20
But is the force F that pushes the point A of the car also a "net"
force?
On 2025-03-22 16:31:37 +0000, Luigi Fortunati said:
In the animation https://www.geogebra.org/classic/sr8fxezb there is the
force F of the hand that pushes the point A of the car.
=20
The force F that pushes the car is certainly a "net" force because
there is no one to push the car from the other side.
=20
But is the force F that pushes the point A of the car also a "net"
force?
A net force to the car is not a net force to a part of the car.
Mikko il 23/03/2025 06:44:06 ha scritto:
On 2025-03-22 16:31:37 +0000, Luigi Fortunati said:
In the animation https://www.geogebra.org/classic/sr8fxezb there is the
force F of the hand that pushes the point A of the car.
=20
The force F that pushes the car is certainly a "net" force because
there is no one to push the car from the other side.
=20
But is the force F that pushes the point A of the car also a "net"
force?
A net force to the car is not a net force to a part of the car.
I agree: the force F of the hand is a net force on the car but it is
not a net force on point A.
Consequentially, on point A there must be *also* a force acting
contrary to the force F.
So, does the blue reaction contrary force FR of my animation act only
on the hand that pushes (as you all keep saying) or does it act *also*
on point A of the car?
theOn 2025-03-22 16:31:37 +0000, Luigi Fortunati said:
=20
In the animation https://www.geogebra.org/classic/sr8fxezb there is =
=20=20force F of the hand that pushes the point A of the car.=20
=3D20
The force F that pushes the car is certainly a "net" force because
there is no one to push the car from the other side.
=3D20
But is the force F that pushes the point A of the car also a "net"
force?
A net force to the car is not a net force to a part of the car.
I agree: the force F of the hand is a net force on the car but it is=20
not a net force on point A.
=20
Consequentially, on point A there must be *also* a force acting=20
contrary to the force F.
=20
So, does the blue reaction contrary force FR of my animation act only=20
on the hand that pushes (as you all keep saying) or does it act *also*=
on point A of the car?
The interactions are between material parts. A point does not interact.
theOn 2025-03-22 16:31:37 +0000, Luigi Fortunati said:
In the animation https://www.geogebra.org/classic/sr8fxezb there is =
force F of the hand that pushes the point A of the car.
The force F that pushes the car is certainly a "net" force because
there is no one to push the car from the other side.
But is the force F that pushes the point A of the car also a "net"
force?
A net force to the car is not a net force to a part of the car.
I agree: the force F of the hand is a net force on the car but it is
not a net force on point A.
Consequentially, on point A there must be *also* a force acting
contrary to the force F.
So, does the blue reaction contrary force FR of my animation act only
on the hand that pushes (as you all keep saying) or does it act *also*=
on point A of the car?
The interactions are between material parts. A point does not interact.
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