From Newsgroup: sci.electronics.basics

Hi guys,

I need to make up a 15k 4 Watt resistor from a selection of half Watt
resistors in parallel. But the math is a bit complex for me. Any ideas
how I could do this please? I'm relatively new to electronics. I have
a ton of half watters to use so any values you come up with I shou,d
have

TIA

Dan
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From Newsgroup: sci.electronics.basics


Same resistors in parallel divide... for 4 watts out of 0.5 watters you
need eight resistors, so 8x the value: 8 * 15k = 120K

(because 8 120k resistors in parallel, divide by 8, is 15k)
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From Newsgroup: sci.electronics.basics

On Tue, 25 Jul 2023 15:18:40 -0400, DJ Delorie <dj@delorie.com> wrote:

Same resistors in parallel divide... for 4 watts out of 0.5 watters you
need eight resistors, so 8x the value: 8 * 15k = 120K

(because 8 120k resistors in parallel, divide by 8, is 15k)

Superb! Many htankss!
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From Newsgroup: sci.electronics.basics

In article <8s90ci1ghb40pef22nofi1s7ddgbdg86u8@4ax.com>, dhg99908
@hotmail.se says...

Same resistors in parallel divide... for 4 watts out of 0.5 watters you >need eight resistors, so 8x the value: 8 * 15k = 120K

(because 8 120k resistors in parallel, divide by 8, is 15k)

Superb! Many htankss!

Same resistors in series or parallel is just the simple multiplyer or devidisin.

Same with capacitors except the mul and devide is reversed.

It only falls into that long drawn out formular of the recipical of the recipical for more than 2 or the product over the sum for 2 of different values.


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