• 230. FIND THE TRIANGLE

    From David Entwistle@qnivq.ragjvfgyr@ogvagrearg.pbz to rec.puzzles on Sun Dec 28 19:04:43 2025
    From Newsgroup: rec.puzzles

    From '536 Puzzles and Curious Problems' by Henry Ernest Dudeney.

    The sides and height of a triangle are four consecutive whole numbers.
    What is the area of the triangle?
    --
    David Entwistle
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  • From Richard Harnden@richard.nospam@gmail.invalid to rec.puzzles on Tue Dec 30 10:57:16 2025
    From Newsgroup: rec.puzzles

    On 28/12/2025 19:04, David Entwistle wrote:
    From '536 Puzzles and Curious Problems' by Henry Ernest Dudeney.

    The sides and height of a triangle are four consecutive whole numbers.
    What is the area of the triangle?

    Using Heron's Fomular <https://en.wikipedia.org/wiki/Heron%27s_formula>

    The height (h) must be less than the shortest side (a),
    so: h < a (=h+1) < b (=h+2) < c (=h+3)

    The area (A) is 0.25 * sqrt((4a^2b^2) - (a^2 + b^2 - c^2)^2
    And check the height with: 2A / b

    Wrote a program to brute force that and the only thing that works is:

    $ ./a.out
    h = 12, a = 13, b = 14, c = 15 ... area = 84









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  • From richard@richard@cogsci.ed.ac.uk (Richard Tobin) to rec.puzzles on Wed Dec 31 11:36:27 2025
    From Newsgroup: rec.puzzles

    In article <10irv0b$f5oh$1@dont-email.me>,
    David Entwistle <qnivq.ragjvfgyr@ogvagrearg.pbz> wrote:
    From '536 Puzzles and Curious Problems' by Henry Ernest Dudeney.

    The sides and height of a triangle are four consecutive whole numbers.
    What is the area of the triangle?

    0

    The sides are 1, 2, and 3.

    -- Richard


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  • From richard@richard@cogsci.ed.ac.uk (Richard Tobin) to rec.puzzles on Wed Dec 31 12:49:14 2025
    From Newsgroup: rec.puzzles

    In article <10j0b6e$1nsg6$1@dont-email.me>,
    Richard Harnden <nospam.harnden@invalid.com> wrote:

    The height (h) must be less than the shortest side (a),

    Not true of triangles in general - for example, a 3,4,5 triangle has
    height 4 from the 3 side.

    At least two of the sides are at least as long as the height, but we
    could conceivably have a triangle where a, h, b, c are consecutive
    integers. Suppose there is one.

    Writing h=a+1, b=a+2, c=a+3 we can use Heron's formula to get

    4a^2(a+1)^2 = (3a+5)(a+5)(a+1)(a-1)

    which is a quartic. Solving numerically (google will do this for you!)
    we get a ~= 1.262 so the triangle with sides 1.262, 3.262, 4.262
    has a height 2.262. Unfortunately these are not integers.

    We can use the same approach to find the correct answer. If the
    height is smaller than any of the sides, we have a=h+1, b=h+2, c=h+3
    and depending on which side we take as the base we have

    4h^2(h+1)^2 = (3h+6)(h+4)(h+2)h
    or
    4h^2(h+2)^2 = (3h+6)(h+4)(h+2)h
    or
    4h^2(h+3)^2 = (3h+6)(h+4)(h+2)h

    The first and third need numerical solution and produce non-integers.
    But the middle one gives us

    4h(h+2) = (3h+6)(h+4)
    4h = 3(h+4)
    h = 12

    -- Richard
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  • From Charlie Roberts@croberts@gmail.com to rec.puzzles on Wed Dec 31 16:25:05 2025
    From Newsgroup: rec.puzzles

    On Wed, 31 Dec 2025 12:49:14 -0000 (UTC), richard@cogsci.ed.ac.uk
    (Richard Tobin) wrote:

    In article <10j0b6e$1nsg6$1@dont-email.me>,
    Richard Harnden <nospam.harnden@invalid.com> wrote:

    The height (h) must be less than the shortest side (a),

    This is a remarkable insight, but I had never heard it said
    before .....

    Not true of triangles in general - for example, a 3,4,5 triangle has
    height 4 from the 3 side.

    ... perhaps because it is not true in general. Richard has already
    given an example, but this could be "worse". When you consider
    obtuse angle triangles, you can make one of the sides including
    the obtuse angle as small as one likes, while maintaing the same
    altitude. This is well illustrated in Wikipedia's entry for triangle
    altitudes:

    https://en.wikipedia.org/wiki/Altitude_(triangle)

    In the first figure, we can make BC as small as we wish while
    keeping the altituted AD fixed.

    We can use the same approach to find the correct answer. If the
    height is smaller than any of the sides, we have a=h+1, b=h+2, c=h+3
    and depending on which side we take as the base we have

    4h^2(h+1)^2 = (3h+6)(h+4)(h+2)h
    or
    4h^2(h+2)^2 = (3h+6)(h+4)(h+2)h
    or
    4h^2(h+3)^2 = (3h+6)(h+4)(h+2)h

    The first and third need numerical solution and produce non-integers.
    But the middle one gives us

    4h(h+2) = (3h+6)(h+4)
    4h = 3(h+4)
    h = 12

    -- Richard

    Excellent!


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  • From Charlie Roberts@croberts@gmail.com to rec.puzzles on Wed Dec 31 16:26:21 2025
    From Newsgroup: rec.puzzles

    On Wed, 31 Dec 2025 11:36:27 -0000 (UTC), richard@cogsci.ed.ac.uk
    (Richard Tobin) wrote:

    In article <10irv0b$f5oh$1@dont-email.me>,
    David Entwistle <qnivq.ragjvfgyr@ogvagrearg.pbz> wrote:
    From '536 Puzzles and Curious Problems' by Henry Ernest Dudeney.

    The sides and height of a triangle are four consecutive whole numbers. >>What is the area of the triangle?

    0

    The sides are 1, 2, and 3.

    -- Richard


    Even better! You need a special medal for this one!!
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  • From Charlie Roberts@croberts@gmail.com to rec.puzzles on Wed Dec 31 16:30:56 2025
    From Newsgroup: rec.puzzles

    On Wed, 31 Dec 2025 16:26:21 -0500, Charlie Roberts
    <croberts@gmail.com> wrote:

    On Wed, 31 Dec 2025 11:36:27 -0000 (UTC), richard@cogsci.ed.ac.uk
    (Richard Tobin) wrote:

    In article <10irv0b$f5oh$1@dont-email.me>,
    David Entwistle <qnivq.ragjvfgyr@ogvagrearg.pbz> wrote:
    From '536 Puzzles and Curious Problems' by Henry Ernest Dudeney.

    The sides and height of a triangle are four consecutive whole numbers. >>>What is the area of the triangle?

    0

    The sides are 1, 2, and 3.

    -- Richard


    Even better! You need a special medal for this one!!

    Actually, I raced past this without thinking. In his post,
    Richard H states that


    The height (h) must be less than the shortest side (a),
    so: h < a (=h+1) < b (=h+2) < c (=h+3)
    <<

    Fleetingly, I thought of h = 0 (a valid integer) .... but
    I was not bright enough to catch the irony and subtlety :-(


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  • From Phil Carmody@pc+usenet@asdf.org to rec.puzzles on Sun Jan 11 15:24:40 2026
    From Newsgroup: rec.puzzles

    richard@cogsci.ed.ac.uk (Richard Tobin) writes:
    In article <10irv0b$f5oh$1@dont-email.me>,
    David Entwistle <qnivq.ragjvfgyr@ogvagrearg.pbz> wrote:
    From '536 Puzzles and Curious Problems' by Henry Ernest Dudeney.

    The sides and height of a triangle are four consecutive whole numbers. >>What is the area of the triangle?

    0

    The sides are 1, 2, and 3.

    You degenerate, you!

    Phil
    --
    We are no longer hunters and nomads. No longer awed and frightened, as we have gained some understanding of the world in which we live. As such, we can cast aside childish remnants from the dawn of our civilization.
    -- NotSanguine on SoylentNews, after Eugen Weber in /The Western Tradition/
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  • From Charlie Roberts@croberts@gmail.com to rec.puzzles on Tue Jan 13 15:40:30 2026
    From Newsgroup: rec.puzzles

    On Sun, 11 Jan 2026 15:24:40 +0200, Phil Carmody <pc+usenet@asdf.org>
    wrote:

    richard@cogsci.ed.ac.uk (Richard Tobin) writes:
    In article <10irv0b$f5oh$1@dont-email.me>,
    David Entwistle <qnivq.ragjvfgyr@ogvagrearg.pbz> wrote:
    From '536 Puzzles and Curious Problems' by Henry Ernest Dudeney.

    The sides and height of a triangle are four consecutive whole numbers. >>>What is the area of the triangle?

    0

    The sides are 1, 2, and 3.

    You degenerate, you!

    Phil

    Right on!

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