At least two types of undecidable problems.
Notably, Prop5 may exlain why Collatz Problem cannot be 'officially' proved following syllogistic production-arule. https://sourceforge.net/projects/cscall/files/MisFiles/Coll-proof-en.txt/download
https://sourceforge.net/projects/cscall/files/MisFiles/RealNumber2-zh.txt/download
...[cut]
Prop 4: Procedural statement contains undecidable statements.
Proof:
bool H(void(*)()); // Let H be a decision procedure. H(D)==true iff D()
// terminates normally.
// If H exists, then there is a D similar to the liar paradox, making
// H(D) undecidable.
void D() {
if(H(D) == true) for(;;){};
}
If H is considered a propositional statement, then this proposition is
undecidable.
Note: The proof of the classical Halting Problem is often summarized in the
above manner, but the content is quite different and does not involve
infinite self-references.
Note: Another type of proposition involving infinite self-reference, like the
'honest person's paradox,' is also non-terminating, such as:
bool P() { // "My words is true"
return P();
}
Prop5: Peano's axiomatic system cannot prove that infinity is a natural number.
Proof: The successor generator S does not terminate. If the meaning of 'proof'
must be in the form like syllogistic production, then the Peano
axiomatic system cannot produce the statement "reRreerao". -------------------------------
Thank olcott, who voluntarily tries the opposite, even sold his soul in the Lake
of Fire for the last >20 years for the opposite, and still failed.
On 1/26/26 12:48 PM, wij wrote:
At least two types of undecidable problems.
Notably, Prop5 may exlain why Collatz Problem cannot be 'officially' proved following syllogistic production-arule. https://sourceforge.net/projects/cscall/files/MisFiles/Coll-proof-en.txt/download
https://sourceforge.net/projects/cscall/files/MisFiles/RealNumber2-zh.txt/download
...[cut]
Prop 4: Procedural statement contains undecidable statements.
-a-a Proof:
-a-a-a-a-a-a-a-a bool H(void(*)()); // Let H be a decision procedure. H(D)==true iff D()
-a-a-a-a-a-a-a-a-a-a-a-a-a-a-a-a-a-a-a-a-a-a-a-a-a-a-a // terminates normally.
-a-a-a-a-a-a-a-a // If H exists, then there is a D similar to the liar paradox, making
-a-a-a-a-a-a-a-a // H(D) undecidable.
-a-a-a-a-a-a-a-a void D() {
-a-a-a-a-a-a-a-a-a-a if(H(D) == true) for(;;){};
-a-a-a-a-a-a-a-a }
-a-a-a-a-a-a-a-a If H is considered a propositional statement, then this proposition is
-a-a-a-a-a-a-a-a undecidable.
-a-a Note: The proof of the classical Halting Problem is often summarized in the
-a-a-a-a-a-a-a-a above manner, but the content is quite different and does not involve
-a-a-a-a-a-a-a-a infinite self-references.
-a-a Note: Another type of proposition involving infinite self-reference, like the
-a-a-a-a-a-a-a-a 'honest person's paradox,' is also non-terminating, such as:
-a-a-a-a-a-a-a-a-a-a-a bool P() {-a-a-a // "My words is true" -a-a-a-a-a-a-a-a-a-a-a-a-a return P();
-a-a-a-a-a-a-a-a-a-a-a }
Prop5: Peano's axiomatic system cannot prove that infinity is a natural number.
-a-a Proof: The successor generator S does not terminate. If the meaning of 'proof'
-a-a-a-a-a-a-a-a must be in the form like syllogistic production, then the Peano
-a-a-a-a-a-a-a-a axiomatic system cannot produce the statement "reRreerao". -------------------------------
Thank olcott, who voluntarily tries the opposite, even sold his soul in the Lake
of Fire for the last >20 years for the opposite, and still failed.
But "infinity" isn't considered a natural number, as it isn't the "successor" of any given natural number, which is how we build them, soIt not the that problem of what you 'consider'. You need to prove it in PA! Successor only produces 1,S(1),SS(1),SSS(1),... PA does not specify termination condition, otherwise I think there will be a problem as an axiom. Particularly,-a
not being able to prove it is a good thing.
Some "alternate models" allow for other roots of succession, which allowI don't know that "alternate models" is. But, if you say "that isn't the basic PA",-a
us to define an w (omega) as the first trans-finite "number" and build
up that first order of trans-finite numbers. But that isn't the basic PA
Note, in your two types of undecidable statements, the Halting ProblemI have reason to see Undecidable is based on TM model, not traditional logic.
is of the form that is inherently undecidable, as any presumed solution creates a contradiction.
The second form might be deciable if some other information is available about the statement.How does proposition "My words is true" is decidable (infinite self-reference)? --- Synchronet 3.21b-Linux NewsLink 1.2
On Mon, 2026-01-26 at 13:39 -0500, Richard Damon wrote:
On 1/26/26 12:48 PM, wij wrote:
At least two types of undecidable problems.
Notably, Prop5 may exlain why Collatz Problem cannot be 'officially' proved >>> following syllogistic production-arule.
https://sourceforge.net/projects/cscall/files/MisFiles/Coll-proof-en.txt/download
https://sourceforge.net/projects/cscall/files/MisFiles/RealNumber2-zh.txt/download
...[cut]
Prop 4: Procedural statement contains undecidable statements.
-a-a Proof:
-a-a-a-a-a-a-a-a bool H(void(*)()); // Let H be a decision procedure. H(D)==true iff D()
-a-a-a-a-a-a-a-a-a-a-a-a-a-a-a-a-a-a-a-a-a-a-a-a-a-a-a // terminates normally.
-a-a-a-a-a-a-a-a // If H exists, then there is a D similar to the liar paradox, making
-a-a-a-a-a-a-a-a // H(D) undecidable.
-a-a-a-a-a-a-a-a void D() {
-a-a-a-a-a-a-a-a-a-a if(H(D) == true) for(;;){};
-a-a-a-a-a-a-a-a }
-a-a-a-a-a-a-a-a If H is considered a propositional statement, then this proposition is
-a-a-a-a-a-a-a-a undecidable.
-a-a Note: The proof of the classical Halting Problem is often summarized in the
-a-a-a-a-a-a-a-a above manner, but the content is quite different and does not involve
-a-a-a-a-a-a-a-a infinite self-references.
-a-a Note: Another type of proposition involving infinite self-reference, like the
-a-a-a-a-a-a-a-a 'honest person's paradox,' is also non-terminating, such as:
-a-a-a-a-a-a-a-a-a-a-a bool P() {-a-a-a // "My words is true"
-a-a-a-a-a-a-a-a-a-a-a-a-a return P();
-a-a-a-a-a-a-a-a-a-a-a }
Prop5: Peano's axiomatic system cannot prove that infinity is a natural number.
-a-a Proof: The successor generator S does not terminate. If the meaning of 'proof'
-a-a-a-a-a-a-a-a must be in the form like syllogistic production, then the Peano
-a-a-a-a-a-a-a-a axiomatic system cannot produce the statement "reRreerao".
-------------------------------
Thank olcott, who voluntarily tries the opposite, even sold his soul in the Lake
of Fire for the last >20 years for the opposite, and still failed.
But "infinity" isn't considered a natural number, as it isn't the
"successor" of any given natural number, which is how we build them, so
not being able to prove it is a good thing.
It not the that problem of what you 'consider'. You need to prove it in PA! Successor only produces 1,S(1),SS(1),SSS(1),... PA does not specify termination
condition, otherwise I think there will be a problem as an axiom. Particularly,
the usual 'natural number' is not strictly N.
Some "alternate models" allow for other roots of succession, which allow
us to define an w (omega) as the first trans-finite "number" and build
up that first order of trans-finite numbers. But that isn't the basic PA
I don't know that "alternate models" is. But, if you say "that isn't the basic PA",
then I may safely ignore this section.
Note, in your two types of undecidable statements, the Halting Problem
is of the form that is inherently undecidable, as any presumed solution
creates a contradiction.
I have reason to see Undecidable is based on TM model, not traditional logic.
The second form might be deciable if some other information is available
about the statement.
How does proposition "My words is true" is decidable (infinite self-reference)?
Prop5: Peano's axiomatic system cannot prove that infinity is a
natural number.
On 1/26/2026 11:48 AM, wij wrote:
At least two types of undecidable problems.
reR is not a number it is the process of more.Agree. So we can count N, from 1 to .... more, endless more.
Notably, Prop5 may exlain why Collatz Problem cannot be 'officially' proved following syllogistic production-arule. https://sourceforge.net/projects/cscall/files/MisFiles/Coll-proof-en.txt/download
https://sourceforge.net/projects/cscall/files/MisFiles/RealNumber2-zh.txt/download
...[cut]
Prop 4: Procedural statement contains undecidable statements.
-a-a Proof:
-a-a-a-a-a-a-a-a bool H(void(*)()); // Let H be a decision procedure. H(D)==true iff D()
-a-a-a-a-a-a-a-a-a-a-a-a-a-a-a-a-a-a-a-a-a-a-a-a-a-a-a // terminates normally.
-a-a-a-a-a-a-a-a // If H exists, then there is a D similar to the liar paradox, making
-a-a-a-a-a-a-a-a // H(D) undecidable.
-a-a-a-a-a-a-a-a void D() {
-a-a-a-a-a-a-a-a-a-a if(H(D) == true) for(;;){};
-a-a-a-a-a-a-a-a }
-a-a-a-a-a-a-a-a If H is considered a propositional statement, then this proposition is
-a-a-a-a-a-a-a-a undecidable.
-a-a Note: The proof of the classical Halting Problem is often summarized in the
-a-a-a-a-a-a-a-a above manner, but the content is quite different and does not involve
-a-a-a-a-a-a-a-a infinite self-references.
-a-a Note: Another type of proposition involving infinite self-reference, like the
-a-a-a-a-a-a-a-a 'honest person's paradox,' is also non-terminating, such as:
-a-a-a-a-a-a-a-a-a-a-a bool P() {-a-a-a // "My words is true" -a-a-a-a-a-a-a-a-a-a-a-a-a return P();
-a-a-a-a-a-a-a-a-a-a-a }
Prop5: Peano's axiomatic system cannot prove that infinity is a natural number.
-a-a Proof: The successor generator S does not terminate. If the meaning of 'proof'
-a-a-a-a-a-a-a-a must be in the form like syllogistic production, then the Peano
-a-a-a-a-a-a-a-a axiomatic system cannot produce the statement "reRreerao". -------------------------------
Thank olcott, who voluntarily tries the opposite, even sold his soul in the Lake
of Fire for the last >20 years for the opposite, and still failed.
On Tue, 2026-01-27 at 14:50 -0600, olcott wrote:
On 1/26/2026 11:48 AM, wij wrote:
At least two types of undecidable problems.
reR is not a number it is the process of more.
Agree. So we can count N, from 1 to .... more, endless more.
Notably, Prop5 may exlain why Collatz Problem cannot be 'officially' proved >>> following syllogistic production-arule.
https://sourceforge.net/projects/cscall/files/MisFiles/Coll-proof-en.txt/download
https://sourceforge.net/projects/cscall/files/MisFiles/RealNumber2-zh.txt/download
...[cut]
Prop 4: Procedural statement contains undecidable statements.
-a-a Proof:
-a-a-a-a-a-a-a-a bool H(void(*)()); // Let H be a decision procedure. H(D)==true iff D()
-a-a-a-a-a-a-a-a-a-a-a-a-a-a-a-a-a-a-a-a-a-a-a-a-a-a-a // terminates normally.
-a-a-a-a-a-a-a-a // If H exists, then there is a D similar to the liar paradox, making
-a-a-a-a-a-a-a-a // H(D) undecidable.
-a-a-a-a-a-a-a-a void D() {
-a-a-a-a-a-a-a-a-a-a if(H(D) == true) for(;;){};
-a-a-a-a-a-a-a-a }
-a-a-a-a-a-a-a-a If H is considered a propositional statement, then this proposition is
-a-a-a-a-a-a-a-a undecidable.
-a-a Note: The proof of the classical Halting Problem is often summarized in the
-a-a-a-a-a-a-a-a above manner, but the content is quite different and does not involve
-a-a-a-a-a-a-a-a infinite self-references.
-a-a Note: Another type of proposition involving infinite self-reference, like the
-a-a-a-a-a-a-a-a 'honest person's paradox,' is also non-terminating, such as:
-a-a-a-a-a-a-a-a-a-a-a bool P() {-a-a-a // "My words is true"
-a-a-a-a-a-a-a-a-a-a-a-a-a return P();
-a-a-a-a-a-a-a-a-a-a-a }
Prop5: Peano's axiomatic system cannot prove that infinity is a natural number.
-a-a Proof: The successor generator S does not terminate. If the meaning of 'proof'
-a-a-a-a-a-a-a-a must be in the form like syllogistic production, then the Peano
-a-a-a-a-a-a-a-a axiomatic system cannot produce the statement "reRreerao".
-------------------------------
Thank olcott, who voluntarily tries the opposite, even sold his soul in the Lake
of Fire for the last >20 years for the opposite, and still failed.
On Tue, 2026-01-27 at 10:25 +0200, Mikko wrote:
On 26/01/2026 19:48, wij wrote:
Prop5: Peano's axiomatic system cannot prove that infinity is a
natural number.
In the language of PA you can't even say that infinity is a number.
But every natural number except 0 is the successor of some other
natural number so if infinity is not 0 it is the successor of some
other natural number.
Agree.
....[quote]
Prop5: Peano's axiomatic system cannot prove that infinity is or is not a
natural number.
Proof: The successor generator S does not terminate. If the meaning of 'proof'
must be in the form like syllogistic production, then the Peano
axiomatic system cannot produce the statement like "reRreerao","reRreerao".
-------
I added this proposition to explain, like many other hard problems, why proving
Collatz Problem is difficult (except using algorithm (TM model)).
It is deep. IMO, many mathematical 'difficult' problems are based on illusion that "too small is zero".
On 1/26/2026 11:48 AM, wij wrote:
At least two types of undecidable problems.
reR is not a number it is the process of more.
On 27/01/2026 22:50, olcott wrote:
On 1/26/2026 11:48 AM, wij wrote:
At least two types of undecidable problems.
reR is not a number it is the process of more.
In an extended number system reR can be a number. Sometimes it is useful
to extend a number system with one or two extra numbers.
On 29/01/2026 09:21, Mikko wrote:
In an extended number system reR can be a number. Sometimes it is usefulHow do you characterise an object as a number vs some other denomination?
to extend a number system with one or two extra numbers.
On 29/01/2026 09:21, Mikko wrote:
On 27/01/2026 22:50, olcott wrote:
On 1/26/2026 11:48 AM, wij wrote:
At least two types of undecidable problems.
reR is not a number it is the process of more.
In an extended number system reR can be a number. Sometimes it is useful
to extend a number system with one or two extra numbers.
How do you characterise an object as a number vs some other denomination?
On 27/01/2026 22:50, olcott wrote:
On 1/26/2026 11:48 AM, wij wrote:
At least two types of undecidable problems.
reR is not a number it is the process of more.
In an extended number system reR can be a number. Sometimes it is useful
to extend a number system with one or two extra numbers.
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