• Basically, PNN is delusional because...

    From Rufus Ruffian@ru@ru.ru to talk-origins on Thu Aug 21 15:33:24 2025
    From Newsgroup: talk.origins

    E.Laureti <user2039@newsgrouper.org.invalid> wrote:

    Vincent Maycock <ma.ycock@gm.ail.com> posted:

    Briefly, how are you changing the field self-interaction to increase >>>>the thrust of your PNN vehicle? Or are there other methods that you're >>>>using to accomplish that crucial goal?

    Yes, methods:

    1) Lower the impedance of the dipole

    2) Increase the current

    And are those things difficult to accomplish?

    To lower the impedance of a dipole fed at high frequency is not so >simple, one would have to at least use silver wires, at least.

    Firstly, you have to match the impedance of your "dipole" load to the RF
    source and to the transmission line.

    There are ways to lower the impedance of the radiating element, such as increasing the diameter (which lowers the Q as well). Copper tubing is
    great. For impedance matching, a transformer will work. You also need a
    balun, as explained before, and there are simple, slick ways to realize
    a balun and impedance-matching transformer all in one, using
    transmission line or antenna stubs.

    However. Simply more current isn't going to solve your problem. The
    velocity of charge carriers is just as important. You can have high
    current drifting lazily along the element, and it won't give you vXB
    force. You need to know the bulk drift rate of the electrons. You also
    need to know the current distribution along the dipole.

    Silver wire isn't an answer. Element RF impedance is determined by the
    geometry of the element. Metal conductivity has less to do with it.
    Plus, "wire" (presumably thin) is going to give you high impedance and
    high Q. Also, google "skin effect".

    What you are building is basically an antenna. Antennas are not known
    for producing force, if you hadn't noticed.

    Then there's the unbalanced coax feed blooper, which you don't seem to
    realize.

    Any vXB force is applied between the dipole and the magnets, not
    externally, and that's your foremost miscalculation.

    Your RF half-cycles are still canceling out all your alleged force.

    I can't see why you are even using RF. Can you explain that? A DC loop
    in 'n out the B field would work just as well, being infinitely simpler.

    A TV picture tube has an electron beam, guided by vXB force using the
    magnets in the yoke. Shouldn't that produce thrust? Perhaps you could
    just use a TV picture tube for your space propulsion system? As a side
    benefit, it would entertain the astronauts all the way to Mars.

    I realize you can't answer any of these points, but your retorts are
    endearing.


    And you're saying those cost too much to try to use?

    Second, and more important, to increase the current, all the circuitry >must *support* high currents at high frequency, and some electronic >components just melt under such stress.

    Which ones are melting down,

    The "designer".

    and why can't you replace them

    Because... :

    $$$$$$ and to pay several engineers...

    You're building a device that will revolutionize space travel, and no
    one involved can do any engineering, let alone the physics? So you have
    to solicit investors and free advice on Usenet?

    Lord have mercy.

    --- Synchronet 3.21a-Linux NewsLink 1.2
  • From Von Ottone@pnn@pnn.org to talk-origins on Fri Aug 22 04:16:50 2025
    From Newsgroup: talk.origins

    On Thu, 21 Aug 2025 15:33:24 -0700, Rufus Ruffian <ru@ru.ru> wrote:

    E.Laureti <user2039@newsgrouper.org.invalid> wrote:

    Vincent Maycock <ma.ycock@gm.ail.com> posted:

    Briefly, how are you changing the field self-interaction to increase >> > >>>>the thrust of your PNN vehicle? Or are there other methods that you're >> > >>>>using to accomplish that crucial goal?

    Yes, methods:

    1) Lower the impedance of the dipole

    2) Increase the current

    And are those things difficult to accomplish?

    To lower the impedance of a dipole fed at high frequency is not so
    simple, one would have to at least use silver wires, at least.

    Firstly, you have to match the impedance of your "dipole" load to the RF >source and to the transmission line.

    There are ways to lower the impedance of the radiating element, such as >increasing the diameter (which lowers the Q as well). Copper tubing is
    great. For impedance matching, a transformer will work. You also need a >balun, as explained before, and there are simple, slick ways to realize
    a balun and impedance-matching transformer all in one, using
    transmission line or antenna stubs.

    However. Simply more current isn't going to solve your problem. The
    velocity of charge carriers is just as important. You can have high
    current drifting lazily along the element, and it won't give you vXB
    force. You need to know the bulk drift rate of the electrons. You also
    need to know the current distribution along the dipole.

    Silver wire isn't an answer. Element RF impedance is determined by the >geometry of the element. Metal conductivity has less to do with it.
    Plus, "wire" (presumably thin) is going to give you high impedance and
    high Q. Also, google "skin effect".

    What you are building is basically an antenna. Antennas are not known
    for producing force, if you hadn't noticed.

    Then there's the unbalanced coax feed blooper, which you don't seem to >realize.

    Any vXB force is applied between the dipole and the magnets, not
    externally, and that's your foremost miscalculation.

    Your RF half-cycles are still canceling out all your alleged force.

    I can't see why you are even using RF. Can you explain that? A DC loop
    in 'n out the B field would work just as well, being infinitely simpler.

    A TV picture tube has an electron beam, guided by vXB force using the
    magnets in the yoke. Shouldn't that produce thrust? Perhaps you could
    just use a TV picture tube for your space propulsion system? As a side >benefit, it would entertain the astronauts all the way to Mars.

    I realize you can't answer any of these points, but your retorts are >endearing.


    And you're saying those cost too much to try to use?

    Second, and more important, to increase the current, all the circuitry
    must *support* high currents at high frequency, and some electronic
    components just melt under such stress.

    Which ones are melting down,

    The "designer".

    and why can't you replace them

    Because... :

    $$$$$$ and to pay several engineers...

    You're building a device that will revolutionize space travel, and no
    one involved can do any engineering, let alone the physics? So you have
    to solicit investors and free advice on Usenet?

    We also have various ongoing deals with Italian industries to sell the
    F432BA prototype.


    Lord have mercy.

    Amen!


    You have to read the entire www.asps.it site and you will find
    explanations of why what you say is only partly true.

    Yes the dipole impedance must match the impedance of the circuit, but
    then also the circuit must support high currents at high frequency
    (432MHz) for our V-shaped dipole, and electronic components that
    support 432MHz with high currents siimply *do not exist*.

    The components we use just *melt* after one hour of functioning at 250
    Watts, so it is not possible for now to feed the circuit with higher
    currents.

    If you find another way to increase currents I will be happy to pay
    you for the explanation.

    --- Synchronet 3.21a-Linux NewsLink 1.2
  • From Bob Casanova@nospam@buzz.off to talk-origins on Thu Aug 21 21:47:27 2025
    From Newsgroup: talk.origins

    On Thu, 21 Aug 2025 15:33:24 -0700, the following appeared
    in talk.origins, posted by Rufus Ruffian <ru@ru.ru>:

    E.Laureti <user2039@newsgrouper.org.invalid> wrote:

    Vincent Maycock <ma.ycock@gm.ail.com> posted:

    Briefly, how are you changing the field self-interaction to increase >> > >>>>the thrust of your PNN vehicle? Or are there other methods that you're >> > >>>>using to accomplish that crucial goal?

    Yes, methods:

    1) Lower the impedance of the dipole

    2) Increase the current

    And are those things difficult to accomplish?

    To lower the impedance of a dipole fed at high frequency is not so
    simple, one would have to at least use silver wires, at least.

    Firstly, you have to match the impedance of your "dipole" load to the RF >source and to the transmission line.

    There are ways to lower the impedance of the radiating element, such as >increasing the diameter (which lowers the Q as well). Copper tubing is
    great. For impedance matching, a transformer will work. You also need a >balun, as explained before, and there are simple, slick ways to realize
    a balun and impedance-matching transformer all in one, using
    transmission line or antenna stubs.

    However. Simply more current isn't going to solve your problem. The
    velocity of charge carriers is just as important. You can have high
    current drifting lazily along the element, and it won't give you vXB
    force. You need to know the bulk drift rate of the electrons. You also
    need to know the current distribution along the dipole.

    Silver wire isn't an answer. Element RF impedance is determined by the >geometry of the element. Metal conductivity has less to do with it.
    Plus, "wire" (presumably thin) is going to give you high impedance and
    high Q. Also, google "skin effect".

    What you are building is basically an antenna. Antennas are not known
    for producing force, if you hadn't noticed.

    Then there's the unbalanced coax feed blooper, which you don't seem to >realize.

    Any vXB force is applied between the dipole and the magnets, not
    externally, and that's your foremost miscalculation.

    Your RF half-cycles are still canceling out all your alleged force.

    I can't see why you are even using RF. Can you explain that? A DC loop
    in 'n out the B field would work just as well, being infinitely simpler.

    A TV picture tube has an electron beam, guided by vXB force using the
    magnets in the yoke. Shouldn't that produce thrust? Perhaps you could
    just use a TV picture tube for your space propulsion system? As a side >benefit, it would entertain the astronauts all the way to Mars.

    I realize you can't answer any of these points, but your retorts are >endearing.


    And you're saying those cost too much to try to use?

    Second, and more important, to increase the current, all the circuitry
    must *support* high currents at high frequency, and some electronic
    components just melt under such stress.

    Which ones are melting down,

    The "designer".

    and why can't you replace them

    Because... :

    $$$$$$ and to pay several engineers...

    You're building a device that will revolutionize space travel, and no
    one involved can do any engineering, let alone the physics? So you have
    to solicit investors and free advice on Usenet?

    I suspect that "solicit investors" is the key.

    Lord have mercy.

    Indeed.

    --

    Bob C.

    "The most exciting phrase to hear in science,
    the one that heralds new discoveries, is not
    'Eureka!' but 'That's funny...'"

    - Isaac Asimov

    --- Synchronet 3.21a-Linux NewsLink 1.2
  • From Von Ottone@pnn@pnn.org to talk-origins on Fri Aug 22 06:55:00 2025
    From Newsgroup: talk.origins

    On Thu, 21 Aug 2025 21:47:27 -0700, Bob Casanova <nospam@buzz.off>
    wrote:

    On Thu, 21 Aug 2025 15:33:24 -0700, the following appeared
    in talk.origins, posted by Rufus Ruffian <ru@ru.ru>:

    E.Laureti <user2039@newsgrouper.org.invalid> wrote:

    Vincent Maycock <ma.ycock@gm.ail.com> posted:

    Briefly, how are you changing the field self-interaction to increase >>> > >>>>the thrust of your PNN vehicle? Or are there other methods that you're
    using to accomplish that crucial goal?

    Yes, methods:

    1) Lower the impedance of the dipole

    2) Increase the current

    And are those things difficult to accomplish?

    To lower the impedance of a dipole fed at high frequency is not so
    simple, one would have to at least use silver wires, at least.

    Firstly, you have to match the impedance of your "dipole" load to the RF >>source and to the transmission line.

    There are ways to lower the impedance of the radiating element, such as >>increasing the diameter (which lowers the Q as well). Copper tubing is >>great. For impedance matching, a transformer will work. You also need a >>balun, as explained before, and there are simple, slick ways to realize
    a balun and impedance-matching transformer all in one, using
    transmission line or antenna stubs.

    However. Simply more current isn't going to solve your problem. The >>velocity of charge carriers is just as important. You can have high
    current drifting lazily along the element, and it won't give you vXB
    force. You need to know the bulk drift rate of the electrons. You also
    need to know the current distribution along the dipole.

    Silver wire isn't an answer. Element RF impedance is determined by the >>geometry of the element. Metal conductivity has less to do with it.
    Plus, "wire" (presumably thin) is going to give you high impedance and
    high Q. Also, google "skin effect".

    What you are building is basically an antenna. Antennas are not known
    for producing force, if you hadn't noticed.

    Then there's the unbalanced coax feed blooper, which you don't seem to >>realize.

    Any vXB force is applied between the dipole and the magnets, not >>externally, and that's your foremost miscalculation.

    Your RF half-cycles are still canceling out all your alleged force.

    I can't see why you are even using RF. Can you explain that? A DC loop
    in 'n out the B field would work just as well, being infinitely simpler.

    A TV picture tube has an electron beam, guided by vXB force using the >>magnets in the yoke. Shouldn't that produce thrust? Perhaps you could
    just use a TV picture tube for your space propulsion system? As a side >>benefit, it would entertain the astronauts all the way to Mars.

    I realize you can't answer any of these points, but your retorts are >>endearing.


    And you're saying those cost too much to try to use?

    Second, and more important, to increase the current, all the circuitry >>> > >must *support* high currents at high frequency, and some electronic
    components just melt under such stress.

    Which ones are melting down,

    The "designer".

    and why can't you replace them

    Because... :

    $$$$$$ and to pay several engineers...

    You're building a device that will revolutionize space travel, and no
    one involved can do any engineering, let alone the physics? So you have
    to solicit investors and free advice on Usenet?

    I suspect that "solicit investors" is the key.

    My suspicion is that you are a troll


    Lord have mercy.

    Indeed.


    Amen!

    --- Synchronet 3.21a-Linux NewsLink 1.2
  • From E.Laureti@user2039@newsgrouper.org.invalid to talk-origins on Fri Aug 22 05:24:08 2025
    From Newsgroup: talk.origins


    Von Ottone <pnn@pnn.org> posted:

    On Thu, 21 Aug 2025 15:33:24 -0700, Rufus Ruffian <ru@ru.ru> wrote:

    E.Laureti <user2039@newsgrouper.org.invalid> wrote:

    Vincent Maycock <ma.ycock@gm.ail.com> posted:

    Briefly, how are you changing the field self-interaction to increase >> > >>>>the thrust of your PNN vehicle? Or are there other methods that you're
    using to accomplish that crucial goal?

    Yes, methods:

    1) Lower the impedance of the dipole

    2) Increase the current

    And are those things difficult to accomplish?

    To lower the impedance of a dipole fed at high frequency is not so
    simple, one would have to at least use silver wires, at least.

    Firstly, you have to match the impedance of your "dipole" load to the RF >source and to the transmission line.

    There are ways to lower the impedance of the radiating element, such as >increasing the diameter (which lowers the Q as well). Copper tubing is >great. For impedance matching, a transformer will work. You also need a >balun, as explained before, and there are simple, slick ways to realize
    a balun and impedance-matching transformer all in one, using
    transmission line or antenna stubs.

    However. Simply more current isn't going to solve your problem. The >velocity of charge carriers is just as important. You can have high
    current drifting lazily along the element, and it won't give you vXB
    force. You need to know the bulk drift rate of the electrons. You also
    need to know the current distribution along the dipole.

    Silver wire isn't an answer. Element RF impedance is determined by the >geometry of the element. Metal conductivity has less to do with it.
    Plus, "wire" (presumably thin) is going to give you high impedance and
    high Q. Also, google "skin effect".

    What you are building is basically an antenna. Antennas are not known
    for producing force, if you hadn't noticed.

    Then there's the unbalanced coax feed blooper, which you don't seem to >realize.

    Any vXB force is applied between the dipole and the magnets, not >externally, and that's your foremost miscalculation.

    Your RF half-cycles are still canceling out all your alleged force.

    I can't see why you are even using RF. Can you explain that? A DC loop
    in 'n out the B field would work just as well, being infinitely simpler.

    A TV picture tube has an electron beam, guided by vXB force using the >magnets in the yoke. Shouldn't that produce thrust? Perhaps you could
    just use a TV picture tube for your space propulsion system? As a side >benefit, it would entertain the astronauts all the way to Mars.

    I realize you can't answer any of these points, but your retorts are >endearing.


    And you're saying those cost too much to try to use?

    Second, and more important, to increase the current, all the circuitry >> > >must *support* high currents at high frequency, and some electronic
    components just melt under such stress.

    Which ones are melting down,

    The "designer".

    and why can't you replace them

    Because... :

    $$$$$$ and to pay several engineers...

    You're building a device that will revolutionize space travel, and no
    one involved can do any engineering, let alone the physics? So you have
    to solicit investors and free advice on Usenet?

    We also have various ongoing deals with Italian industries to sell the
    F432BA prototype.


    Lord have mercy.

    Amen!


    You have to read the entire www.asps.it site and you will find
    explanations of why what you say is only partly true.

    Yes the dipole impedance must match the impedance of the circuit, but
    then also the circuit must support high currents at high frequency
    (432MHz) for our V-shaped dipole, and electronic components that
    support 432MHz with high currents siimply *do not exist*.

    The components we use just *melt* after one hour of functioning at 250
    Watts, so it is not possible for now to feed the circuit with higher currents.

    If you find another way to increase currents I will be happy to pay
    you for the explanation.


    there is no way to convince with words those who do not see the pnn tests
    or do not reproduce basic experiments on their own.
    As I said in another thread: let them sink happily
    with the Titanic of their certainties :-)

    --- Synchronet 3.21a-Linux NewsLink 1.2