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On 7/26/2024 5:37 AM, IlanMayer wrote:
On Thu, 25 Jul 2024 19:07:56 +0000, HenHanna wrote:
e.g. -------- For the (street) Numbers (1,2,3,4,5,6,7,8)
(1,2,3,4,5) and (7,8) both add up to 15.
“In a given street of houses with consecutive numbers between 50 and
500, find the house number, for which, the sum of numbers on the left is >>> equal to the sum of numbers on the right”
Ramanujan and Strand Puzzle
this was a very interesting puzzle tackled by the genius
Srinivasa Ramanujan. In the year 1914, P.C. Mahalanobis, a Kings
college student in England, got hold of a puzzle from the Strand
magazine.
Solution found at:
https://ubpdqnmathematica.wordpress.com/2021/12/05/ramanujan-and-strand-puzzle/
thanks!
continued fraction of \sqrt{2}, which _is_ satisfying simple.So the solutions to the Strand puzzle can be found from the
Using Mathematica to look at the first 10 convergents
---------- is this (also) easy to do using Lisp or Python???
On Mon, 29 Jul 2024 18:58:21 +0000, HenHanna wrote:
On 7/26/2024 5:37 AM, IlanMayer wrote:
On Thu, 25 Jul 2024 19:07:56 +0000, HenHanna wrote:
e.g. -------- For the (street) Numbers (1,2,3,4,5,6,7,8)
(1,2,3,4,5) and (7,8) both add up to 15.
“In a given street of houses with consecutive numbers between 50 and >>>> 500, find the house number, for which, the sum of numbers on the
left is
equal to the sum of numbers on the right”
Ramanujan and Strand Puzzle
this was a very interesting puzzle tackled by the genius
Srinivasa Ramanujan. In the year 1914, P.C. Mahalanobis, a Kings
college student in England, got hold of a puzzle from the Strand
magazine.
Solution found at:
https://ubpdqnmathematica.wordpress.com/2021/12/05/ramanujan-and-
strand-puzzle/
thanks!
continued fraction of \sqrt{2}, which _is_ satisfying simple.; So the solutions to the Strand puzzle can be found from the
; Using Mathematica to look at the first 10 convergents
---------- is this (also) easy to do using Lisp or Python???
This can be done with Python:
N = 10
a = 1
b = 1
print(str(a) + "/" + str(b))
for n in range(N):
temp = a + 2 * b
b = a + b
a = temp
print(str(a) + "/" + str(b))
On Mon, 29 Jul 2024 18:58:21 +0000, HenHanna wrote:
On 7/26/2024 5:37 AM, IlanMayer wrote:
So the solutions to the Strand puzzle can be found from the
continued fraction of \sqrt{2}, which _is_ satisfying simple.
Using Mathematica to look at the first 10 convergents
---------- is this (also) easy to do using Lisp or Python???
This can be done with Python:
N = 10
a = 1
b = 1
print(str(a) + "/" + str(b))
for n in range(N):
temp = a + 2 * b
b = a + b
a = temp
print(str(a) + "/" + str(b))