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On 18.12.2024 20:46, Salvador Mirzo wrote:
(*) Summary
I wrote a sed script that makes a line replacement after it finds the
right spot. So far so good. Then I added quit command after the
change, but the quit does not seem to take effect---violating my
expectation. I'll appreciate any help on understanding what's going on.
First (before I forget it) change your string comparison '<' to the
numerical comparison operator '-lt' as in: test $# -lt 2 && usage >Otherwise, if you get used to using the wrong operator, you may get
subtle errors in future if you continue that habit.
In article <vk40gi$3g9sm$1@dont-email.me>,
Janis Papanagnou <janis_papanagnou+ng@hotmail.com> wrote:
On 18.12.2024 20:46, Salvador Mirzo wrote:
[...]
First (before I forget it) change your string comparison '<' to the
numerical comparison operator '-lt' as in: test $# -lt 2 && usage
Otherwise, if you get used to using the wrong operator, you may get
subtle errors in future if you continue that habit.
Agreed, in general, but in practice, the need rarely arises.
The idiomatic way to do this is just:
[ $# = 2 ] || usage()
Also, when I need to do more complex arg verification, I use bash's [[ ]] mechanism (Yes, I know OP is using /bin/sh, but there is no reason nowadays not to use bash).
Say I want there to be 2 or 3 args (no other # is
acceptable and the 2nd arg must be numeric. Like this:
[[ $#,$2 =~ ^[23],[0-9]+$ ]] || { echo "Arg error!"; exit; }
Agreed, in general, but in practice, the need rarely arises.
I certainly disagree on this; if you have 10..19 (or 100..199 etc.)
arguments the '<' test just doesn't trigger but '-lt' does. I mean,
why use a wrong operator. If it will only in specific cases produce
correct results, or if it produced in most cases correct results;
it's just the wrong thing.
The idiomatic way to do this is just:
[ $# = 2 ] || usage()
Yes, but I don't use that but prefer (like you) [[...]], an in, say,
Also, when I need to do more complex arg verification, I use bash's [[ ]]
mechanism (Yes, I know OP is using /bin/sh, but there is no reason nowadays >> not to use bash).
If the OP is on Linux the 'sh' might actually be a Bash. If he's,