XPost: comp.sys.mac.advocacy, misc.phone.mobile.iphone
On 2024-11-13 05:10, -hh wrote:
Alan <nuh-uh@nope.com> wrote:
On 2024-11-12 20:57, Andrews wrote:
-hh wrote on Tue, 12 Nov 2024 14:15:44 -0500 :
I've never heard any NASCAR/Indy/F1/etc race announcers> ever mention
the word "catenary" ...
... let alone used it in the alleged context herein of guidance for
optimizing the line in a corner to minimize peak cornering forces.
Had any of you uneducated Apple trolls taken even a single class in
Physics, you'd know centripedal/centrifugal forces exist in the X plane.
Everyone knows that, doofus.
And it's "centripetal" force. With a "T".
And why the sudden change by Arlen to centripetal forces, when his claims have used catenary?
Maybe because he’s not found any TV video of race announcers using the term?
Nah … too quick of a reply for that: he’s either profoundly lazy or
he knows he’s lying.
I think he's the type who's convinced of his own intelligence, but who
actually isn't very bright.
He once saw someone (somewhere) use the word "catenary" in relation to
cars negotiating a curve...
(For all we know, it really was the website with talking about wooden
toy cars)
...and like so many, he just let that become the only "thought" he ever
had about it.
BTW, I can show pretty conclusively that during the phase from turn-in
to the "middle" of the corner, and assuming that braking and lateral
forces are equal (i.e. the "friction circle" IS a circle in the braking hemisphere), then the ideal line through a corner is a parabola; at
least for any corner of 90 degrees or less.
I can also show that that beyond 90 degrees, there will be a segment in
the middle (once you're completely off the brakes) which is purely on a circular arc.
The actual shape of the "exit" half of a corner (from the point where
you slowly start to apply throttle) is much harder to calculate, because
the "hemisphere" of the friction circle... ...isn't a hemisphere at all
times.
--- SoupGate-Win32 v1.05
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