Jochen wrote:

This ...

CL-USER 1 > (loop for i for j in '(a b c) collect (cons i j))

((0 . A) (1 . B) (2 . C))

works perfectly on LispWorks, but not with SBCL

FOR is an unknown keyword in FOR or AS clause in LOOP.

I found a way around it 'for i from 0' but am not sure if there is
another smarter way to achieve this.

I think the canonical way would be

(loop for i upfrom 0
for j in '(a b c)
collect (cons i j))

newLISP

(map (curry list $idx) '(a b c))

((0 a) (1 b) (2 c))

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